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Download previous O/L ICT Past Papers From here –
- 2021 O/L ICT Past Paper and Answers
2021 O/L Marking Scheme - 2020 O/L ICT Past Paper and Answers
2020 O/L Marking Scheme - 2019 O/L Information And Communication Technology Past Paper
2019 O/L Information & Communication Technology Marking Scheme - 2018 O/L Information & Communication Technology Past Paper
2018 O/L Information & Communication Technology Marking Scheme - 2017 O/L Information & Communication Technology Past Paper
2017 O/L Information & Communication Technology Marking Scheme - 2016 O/L Information & Communication Technology Past Paper
2016 O/L Information & Communication Technology Marking Scheme - 2015 O/L Information & Communication Technology Past Paper
2015 O/L Information & Communication Technology Marking Scheme - 2014 O/L Information & Communication Technology Past Paper
2014 O/L Information & Communication Technology Marking Scheme - 2013 O/L Information & Communication Technology Past Paper
2013 O/L Information & Communication Technology Marking Scheme - 2012 O/L Information & Communication Technology Past Paper
2012 O/L Information & Communication Technology Marking Scheme - 2011 O/L Information & Communication Technology Past Paper
2011 O/L Information & Communication Technology Marking Scheme - 2010 O/L Information & Communication Technology Past Paper
2010 O/L Information & Communication Technology Marking Scheme - 2009 O/L Information & Communication Technology Past Paper
2009 O/L Information & Communication Technology Marking Scheme - 2008 O/L Information & Communication Technology Past Paper
2008 O/L Information & Communication Technology Marking Scheme - 2007 O/L Information & Communication Technology Past Paper
2007 O/L Information & Communication Technology Marking Scheme
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Can i get the 2020 ol “English Medium” paper
7th question is missing!
download krnne kohenda, link ekk na ne
I just wanted to point out an error in the marking scheme. The answer for the 37th question in the MCQ paper is 4. 55 not 1.25. I don’t know how this error occurred, but I think they ignored the fact that a “REPEAT UNTIL” loop never stops its execution until the condition that’s been given to it becomes false. In this case, UNTIL count > 0 implies that the value of “sum” will increase to a value greater than 25 because the loop will run the code inside it until count is equal to zero. When count is equal to zero, the value of sum is displayed and that’s the final output.
Here’s a more detailed explanation:
The answer provided in the marking scheme (25) is incorrect because the loop does not terminate after the first iteration. In the pseudocode, the REPEAT…UNTIL loop runs until the condition count > 0 is false. Since the initial value of count is 5, the loop executes multiple times, decrementing count and adding count^2 to sum in each iteration.
The correct calculation is as follows:
Iteration 1: sum = 0 + 5^2 = 25, count = 4
Iteration 2: sum = 25 + 4^2 = 41, count = 3
Iteration 3: sum = 41 + 3^2 = 50, count = 2
Iteration 4: sum = 50 + 2^2 = 54, count = 1
Iteration 5: sum = 54 + 1^2 = 55, count = 0
The loop exits when count = 0, as count > 0 is now false. Thus, the output of the program is 55, not 25. This mistake likely stems from misunderstanding how the UNTIL condition functions.